ASVAB Math Knowledge Practice Test 97612

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3a - 2a = 6a + 3x - 1 for a in terms of x.

\(\frac{1}{3}\)x + 2\(\frac{2}{3}\)
1\(\frac{1}{9}\)x + \(\frac{8}{9}\)
x - \(\frac{3}{13}\)
-1\(\frac{2}{3}\)x + \(\frac{1}{3}\)