When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 3c = -8c + 8z + 1 for c in terms of z.
| \(\frac{5}{7}\)z + \(\frac{3}{7}\) | |
| z + \(\frac{1}{11}\) | |
| -1\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -3\(\frac{4}{5}\)z - \(\frac{2}{5}\) |