When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 8c = -c + 5z + 3 for c in terms of z.
| -2\(\frac{3}{5}\)z + 1\(\frac{3}{5}\) | |
| -\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)z + \(\frac{2}{5}\) | |
| z - \(\frac{2}{3}\) |