ASVAB Math Knowledge Practice Test 979109

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5a - 4a = a + 5z - 1 for a in terms of z.

-1\(\frac{1}{2}\)z + \(\frac{1}{6}\)
-\(\frac{7}{11}\)z + \(\frac{4}{11}\)
\(\frac{2}{7}\)z + 1\(\frac{2}{7}\)
2\(\frac{1}{5}\)z - \(\frac{4}{5}\)