| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
If the base of this triangle is 1 and the height is 5, what is the area?
| 2\(\frac{1}{2}\) | |
| 105 | |
| 48 | |
| 30 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 1 x 5 = \( \frac{5}{2} \) = 2\(\frac{1}{2}\)
To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?
First |
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Odd |
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Last |
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Inside |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.
Which of the following statements about a triangle is not true?
exterior angle = sum of two adjacent interior angles |
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perimeter = sum of side lengths |
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sum of interior angles = 180° |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
On this circle, a line segment connecting point A to point D is called:
radius |
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circumference |
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diameter |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve -4c + 2c = -c - 8y - 5 for c in terms of y.
| \(\frac{7}{9}\)y + \(\frac{2}{9}\) | |
| 1\(\frac{1}{3}\)y + 1 | |
| -\(\frac{1}{3}\)y - 1 | |
| 3\(\frac{1}{3}\)y + 1\(\frac{2}{3}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-4c + 2y = -c - 8y - 5
-4c = -c - 8y - 5 - 2y
-4c + c = -8y - 5 - 2y
-3c = -10y - 5
c = \( \frac{-10y - 5}{-3} \)
c = \( \frac{-10y}{-3} \) + \( \frac{-5}{-3} \)
c = 3\(\frac{1}{3}\)y + 1\(\frac{2}{3}\)