ASVAB Math Knowledge Practice Test 982620 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

The endpoints of this line segment are at (-2, 7) and (2, -5). What is the slope-intercept equation for this line?

41% Answer Correctly
y = 2\(\frac{1}{2}\)x + 3
y = -2\(\frac{1}{2}\)x - 3
y = -3x - 3
y = -3x + 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -5) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)
m = -3

Plugging these values into the slope-intercept equation:

y = -3x + 1


2

Simplify (y + 4)(y - 8)

64% Answer Correctly
y2 + 12y + 32
y2 - 12y + 32
y2 - 4y - 32
y2 + 4y - 32

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 4)(y - 8)
(y x y) + (y x -8) + (4 x y) + (4 x -8)
y2 - 8y + 4y - 32
y2 - 4y - 32


3

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

3

4

2

5


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


4

The dimensions of this cube are height (h) = 8, length (l) = 2, and width (w) = 7. What is the surface area?

51% Answer Correctly
82
172
162
150

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 2 x 7) + (2 x 7 x 8) + (2 x 2 x 8)
sa = (28) + (112) + (32)
sa = 172


5

The dimensions of this cylinder are height (h) = 2 and radius (r) = 5. What is the surface area?

48% Answer Correctly
208π
198π
70π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 2)
sa = 2π(25) + 2π(10)
sa = (2 x 25)π + (2 x 10)π
sa = 50π + 20π
sa = 70π