ASVAB Math Knowledge Practice Test 983550 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

What is 7a5 + 8a5?

74% Answer Correctly
56a5
-1
15a5
a510

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a5 + 8a5 = 15a5


2

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

\({\Delta y \over \Delta x}\)

x-intercept

y-intercept

slope


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


3

If AD = 13 and BD = 3, AB = ?

75% Answer Correctly
2
15
10
20

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 13 - 3
AB = 10


4

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
4\( \sqrt{2} \)
3\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


5

If side a = 8, side b = 4, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{130} \)
\( \sqrt{80} \)
\( \sqrt{128} \)
\( \sqrt{85} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 82 + 42
c2 = 64 + 16
c2 = 80
c = \( \sqrt{80} \)