| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
What is 7a5 + 8a5?
| 56a5 | |
| -1 | |
| 15a5 | |
| a510 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a5 + 8a5 = 15a5
Which of the following is not required to define the slope-intercept equation for a line?
\({\Delta y \over \Delta x}\) |
|
x-intercept |
|
y-intercept |
|
slope |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
If AD = 13 and BD = 3, AB = ?
| 2 | |
| 15 | |
| 10 | |
| 20 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf the area of this square is 4, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
If side a = 8, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{130} \) | |
| \( \sqrt{80} \) | |
| \( \sqrt{128} \) | |
| \( \sqrt{85} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 42
c2 = 64 + 16
c2 = 80
c = \( \sqrt{80} \)