ASVAB Math Knowledge Practice Test 984840 Results

Your Results Global Average
Questions 5 5
Correct 0 2.75
Score 0% 55%

Review

1

If the base of this triangle is 2 and the height is 6, what is the area?

58% Answer Correctly
65
30
49
6

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 2 x 6 = \( \frac{12}{2} \) = 6


2

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral, isosceles and right

equilateral and isosceles

equilateral and right

isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


3

Factor y2 + 18y + 81

54% Answer Correctly
(y - 9)(y + 9)
(y + 9)(y + 9)
(y - 9)(y - 9)
(y + 9)(y - 9)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 81 as well and sum (Inside, Outside) to equal 18. For this problem, those two numbers are 9 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 18y + 81
y2 + (9 + 9)y + (9 x 9)
(y + 9)(y + 9)


4

The endpoints of this line segment are at (-2, -5) and (2, 1). What is the slope of this line?

46% Answer Correctly
2\(\frac{1}{2}\)
-1\(\frac{1}{2}\)
1\(\frac{1}{2}\)
-\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -5) and (2, 1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-5.0)}{(2) - (-2)} \) = \( \frac{6}{4} \)
m = 1\(\frac{1}{2}\)


5

Simplify (y + 3)(y + 5)

63% Answer Correctly
y2 - 2y - 15
y2 + 8y + 15
y2 - 8y + 15
y2 + 2y - 15

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 3)(y + 5)
(y x y) + (y x 5) + (3 x y) + (3 x 5)
y2 + 5y + 3y + 15
y2 + 8y + 15