When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 4c = 5c - 3z - 7 for c in terms of z.
| -1\(\frac{1}{4}\)z + 1\(\frac{1}{4}\) | |
| z - 7 | |
| -\(\frac{1}{7}\)z + \(\frac{1}{14}\) | |
| -\(\frac{3}{5}\)z - \(\frac{3}{10}\) |