| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
This diagram represents two parallel lines with a transversal. If c° = 13, what is the value of w°?
| 27 | |
| 13 | |
| 29 | |
| 35 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with c° = 13, the value of w° is 13.
The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?
| y = -2\(\frac{1}{2}\)x + 1 | |
| y = 3x + 2 | |
| y = 2x + 1 | |
| y = \(\frac{1}{2}\)x - 2 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x - 2
Simplify 5a x 7b.
| 35\( \frac{b}{a} \) | |
| 35ab | |
| 12ab | |
| 35a2b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
5a x 7b = (5 x 7) (a x b) = 35ab
If the base of this triangle is 9 and the height is 5, what is the area?
| 33 | |
| 40\(\frac{1}{2}\) | |
| 22\(\frac{1}{2}\) | |
| 67\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 5 = \( \frac{45}{2} \) = 22\(\frac{1}{2}\)
The formula for the area of a circle is which of the following?
c = π d |
|
c = π r2 |
|
c = π r |
|
c = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.