When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 4c = 8c + 3z - 2 for c in terms of z.
| \(\frac{1}{2}\)z + \(\frac{1}{6}\) | |
| -z - 2 | |
| -\(\frac{1}{14}\)z + \(\frac{5}{14}\) | |
| -15z + 2 |