ASVAB Math Knowledge Practice Test 986560

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a - 5a = 5a + 6z + 3 for a in terms of z.

\(\frac{4}{9}\)z + \(\frac{1}{9}\)
-\(\frac{12}{13}\)z + \(\frac{5}{13}\)
-z - \(\frac{3}{11}\)
z - 6