When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 2c = -c - 8z + 9 for c in terms of z.
| -\(\frac{6}{7}\)z + 1\(\frac{2}{7}\) | |
| -\(\frac{9}{11}\)z + \(\frac{7}{11}\) | |
| -3z + 4 | |
| \(\frac{5}{6}\)z - \(\frac{1}{2}\) |