When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7a + 3a = -7a + 4z + 1 for a in terms of z.
| 4\(\frac{1}{3}\)z - 3 | |
| -2\(\frac{4}{5}\)z + 1\(\frac{3}{5}\) | |
| \(\frac{1}{14}\)z + \(\frac{1}{14}\) | |
| \(\frac{4}{7}\)z - \(\frac{1}{7}\) |