To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s²

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c² = a² + b²
c² = 1² + 1²
c² = 2
c = \( \sqrt{2} \)

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

The formula for area is πr²:

a = πr²
a = π(2²)
a = 4π

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(7ab) - (4a²)(5b)
(8 x 7)(a x a x b) - (4 x 5)(a² x b)
(56)(a¹⁺¹ x b) - (20)(a²b)
56a²b - 20a²b
36a²b

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 59° - 56° = 65°