When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8b + b = 9b + 4z + 1 for b in terms of z.
| -2\(\frac{1}{3}\)z + 1 | |
| -3z + 3 | |
| \(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -3z - 1 |