When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = 5c + 3x - 4 for c in terms of x.
| 3\(\frac{1}{4}\)x - 1\(\frac{3}{4}\) | |
| 2x - 2\(\frac{1}{2}\) | |
| -x - 4 | |
| -x + \(\frac{9}{14}\) |