| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
Factor y2 - 9y + 8
| (y + 8)(y - 1) | |
| (y - 8)(y - 1) | |
| (y - 8)(y + 1) | |
| (y + 8)(y + 1) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 8 as well and sum (Inside, Outside) to equal -9. For this problem, those two numbers are -8 and -1. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 9y + 8
y2 + (-8 - 1)y + (-8 x -1)
(y - 8)(y - 1)
The dimensions of this cylinder are height (h) = 4 and radius (r) = 1. What is the surface area?
| 96π | |
| 10π | |
| 130π | |
| 36π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 4)
sa = 2π(1) + 2π(4)
sa = (2 x 1)π + (2 x 4)π
sa = 2π + 8π
sa = 10π
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
|
right, acute, obtuse |
|
acute, obtuse, right |
|
right, obtuse, acute |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
What is 6a9 - 4a9?
| 2a9 | |
| 2 | |
| 24a18 | |
| 24a9 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a9 - 4a9 = 2a9
If the area of this square is 4, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)