ASVAB Math Knowledge Practice Test 996325 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

Factor y2 - 9y + 8

53% Answer Correctly
(y + 8)(y - 1)
(y - 8)(y - 1)
(y - 8)(y + 1)
(y + 8)(y + 1)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 8 as well and sum (Inside, Outside) to equal -9. For this problem, those two numbers are -8 and -1. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 9y + 8
y2 + (-8 - 1)y + (-8 x -1)
(y - 8)(y - 1)


2

The dimensions of this cylinder are height (h) = 4 and radius (r) = 1. What is the surface area?

48% Answer Correctly
96π
10π
130π
36π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 4)
sa = 2π(1) + 2π(4)
sa = (2 x 1)π + (2 x 4)π
sa = 2π + 8π
sa = 10π


3

Order the following types of angle from least number of degrees to most number of degrees.

74% Answer Correctly

acute, right, obtuse

right, acute, obtuse

acute, obtuse, right

right, obtuse, acute


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


4

What is 6a9 - 4a9?

73% Answer Correctly
2a9
2
24a18
24a9

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a9 - 4a9 = 2a9


5

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
6\( \sqrt{2} \)
3\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)