The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 4) and (2, -6) so the slope becomes:

Plugging these values into the slope-intercept equation:

y = -2\(\frac{1}{2}\)x - 1

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 8cm + 15cm + 7cm = 30cm

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.

You need to find the value of b so solve the first equation in terms of x:

2b + x = 6
x = 6 - 2b

then substitute the result (6 - 2b) into the second equation:

-6b + 6(6 - 2b) = 2
-6b + (6 x 6) + (6 x -2b) = 2
-6b + 36 - 12b = 2
-6b - 12b = 2 - 36
-18b = -34
b = \( \frac{-34}{-18} \)
b = 1\(\frac{8}{9}\)