ASVAB Math Knowledge Practice Test 997398 Results

Your Results Global Average
Questions 5 5
Correct 0 3.47
Score 0% 69%

Review

1

Simplify 2a x 9b.

86% Answer Correctly
18\( \frac{b}{a} \)
18ab
11ab
18\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

2a x 9b = (2 x 9) (a x b) = 18ab


2

If a = c = 4, b = d = 6, what is the area of this rectangle?

80% Answer Correctly
24
8
42
9

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 4 x 6
a = 24


3

The endpoints of this line segment are at (-2, -6) and (2, -2). What is the slope-intercept equation for this line?

41% Answer Correctly
y = 3x - 4
y = \(\frac{1}{2}\)x - 2
y = x - 2
y = x - 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, -2) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)
m = 1

Plugging these values into the slope-intercept equation:

y = x - 4


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

addition

pairs

division

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 + a2

c2 - a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)