ASVAB Math Knowledge Practice Test 99741 Results

Your Results Global Average
Questions 5 5
Correct 0 3.60
Score 0% 72%

Review

1

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

division

exponents

pairs

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


2

This diagram represents two parallel lines with a transversal. If w° = 36, what is the value of c°?

73% Answer Correctly
15
11
170
36

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with w° = 36, the value of c° is 36.


3

If side a = 2, side b = 1, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{29} \)
\( \sqrt{34} \)
\( \sqrt{26} \)
\( \sqrt{5} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 12
c2 = 4 + 1
c2 = 5
c = \( \sqrt{5} \)


4

If side x = 11cm, side y = 15cm, and side z = 8cm what is the perimeter of this triangle?

85% Answer Correctly
31cm
34cm
28cm
44cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 11cm + 15cm + 8cm = 34cm


5

Solve for c:
8c - 9 = \( \frac{c}{-2} \)

46% Answer Correctly
1\(\frac{1}{17}\)
-1\(\frac{23}{25}\)
12
2\(\frac{16}{19}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

8c - 9 = \( \frac{c}{-2} \)
-2 x (8c - 9) = c
(-2 x 8c) + (-2 x -9) = c
-16c + 18 = c
-16c + 18 - c = 0
-16c - c = -18
-17c = -18
c = \( \frac{-18}{-17} \)
c = 1\(\frac{1}{17}\)