To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 49 as well and sum (Inside, Outside) to equal 14. For this problem, those two numbers are 7 and 7. Then, plug these into a set of binomials using the square root of the First variable (y²):

y² + 14y + 49
y² + (7 + 7)y + (7 x 7)
(y + 7)(y + 7)

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b² + 2b - 20 = -3b + 4
b² + 2b - 20 - 4 = -3b
b² + 2b + 3b - 24 = 0
b² + 5b - 24 = 0

Next, factor the quadratic equation:

b² + 5b - 24 = 0
(b - 3)(b + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 3) or (b + 8) must equal zero:

If (b - 3) = 0, b must equal 3
If (b + 8) = 0, b must equal -8

So the solution is that b = 3 or -8

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 6 + 2 + 4 + 2
p = 14

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 8) so the slope becomes:

Plugging these values into the slope-intercept equation:

y = 2\(\frac{1}{2}\)x + 3

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

5y - 8 < 5 - 6y
5y < 5 - 6y + 8
5y + 6y < 5 + 8
11y < 13
y < \( \frac{13}{11} \)
y < 1\(\frac{2}{11}\)