| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
If the base of this triangle is 6 and the height is 6, what is the area?
| 105 | |
| 91 | |
| 18 | |
| 36 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 6 x 6 = \( \frac{36}{2} \) = 18
The dimensions of this trapezoid are a = 4, b = 3, c = 5, d = 8, and h = 3. What is the area?
| 16 | |
| 37\(\frac{1}{2}\) | |
| 22 | |
| 16\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(3 + 8)(3)
a = ½(11)(3)
a = ½(33) = \( \frac{33}{2} \)
a = 16\(\frac{1}{2}\)
If side a = 8, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{61} \) | |
| \( \sqrt{80} \) | |
| \( \sqrt{34} \) | |
| \( \sqrt{53} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 42
c2 = 64 + 16
c2 = 80
c = \( \sqrt{80} \)
If angle a = 36° and angle b = 31° what is the length of angle c?
| 113° | |
| 118° | |
| 110° | |
| 111° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 36° - 31° = 113°
If angle a = 43° and angle b = 53° what is the length of angle d?
| 130° | |
| 114° | |
| 127° | |
| 137° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 43° - 53° = 84°
So, d° = 53° + 84° = 137°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 43° = 137°