| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
Which of the following is the formula for gravitational potential energy?
\(PE = { 1 \over 2} mg^2\) |
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\(PE = mgh\) |
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\(PE = mg^2h\) |
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\(PE = { 1 \over 2} mv^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
| 0.92 ft. | |
| 0.23 ft. | |
| 0.31 ft. | |
| 0.46 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{55 lbs. \times 1 ft.}{60 lbs.} \) = \( \frac{55 ft⋅lb}{60 lbs.} \) = 0.92 ft.
Which of the following represents how much two materials resist sliding across each other?
normal friction |
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coefficient of friction |
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kinetic friction |
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static friction |
Coefficient of friction (μ) represents how much two materials resist sliding across each other. Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.
Which of these is the formula for force?
F = m/a |
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F = ma |
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F = am2 |
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F = a/m |
Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.
The advantage of using a third-class lever is that it increases:
the mechanical advantage of the lever |
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the speed of the load |
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the distance traveled by the load |
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the force applied to the load |
A third-class lever is used to increase distance traveled by an object in the same direction as the force applied. The fulcrum is at one end of the lever, the object at the other, and the force is applied between them. This lever does not impart a mechanical advantage as the effort force must be greater than the load but does impart extra speed to the load. Examples of third-class levers are shovels and tweezers.