ASVAB Mechanical Comprehension Practice Test 123259 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

What defines the mechanical advantage of a first class lever?

65% Answer Correctly

input force

position of the fulcrum

output distance

output force 


Solution

A first-class lever is used to increase force or distance while changing the direction of the force. The lever pivots on a fulcrum and, when a force is applied to the lever at one side of the fulcrum, the other end moves in the opposite direction. The position of the fulcrum also defines the mechanical advantage of the lever. If the fulcrum is closer to the force being applied, the load can be moved a greater distance at the expense of requiring a greater input force. If the fulcrum is closer to the load, less force is required but the force must be applied over a longer distance. An example of a first-class lever is a seesaw / teeter-totter.


2

Friction between two or more solid objects that are not moving relative to each other is called:

74% Answer Correctly

dynamic friction

static friction

gravitational friction

kinetic friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


3 If the green box weighs 5 lbs. and is 7 ft. from the fulcrum, how far from the fulcrum would a 45 lbs. weight need to be placed to balance the lever?
61% Answer Correctly
2.33 ft.
1.56 ft.
0.78 ft.
0 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{5 lbs. \times 7 ft.}{45 lbs.} \) = \( \frac{35 ft⋅lb}{45 lbs.} \) = 0.78 ft.


4

Which of the following represents how much two materials resist sliding across each other?

53% Answer Correctly

static friction

kinetic friction

coefficient of friction

normal friction


Solution

Coefficient of friction (μ) represents how much two materials resist sliding across each other.  Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.


5

Boyle's law defines the relationship between pressure and volume as:

58% Answer Correctly

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)

\(\frac{P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)

\({P_1}{P_2} = {V_1}{V_2}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)