ASVAB Mechanical Comprehension Practice Test 131001 Results

Your Results Global Average
Questions 5 5
Correct 0 3.61
Score 0% 72%

Review

1 How much resistance could a 110 lb. effort force lift using a block and tackle pulley that has 4 ropes supporting the resistance?
81% Answer Correctly
484 lbs.
441.5 lbs.
1320 lbs.
440 lbs.

Solution

The mechanical advantage (MA) of a block and tackle pulley is equal to the number of times the effort force changes direction. An easy way to count how many times the effort force changes direction is to count the number of ropes that support the resistance which, in this problem, is 4. With a MA of 4, a 110 lbs. effort force could lift 110 lbs. x 4 = 440 lbs. resistance.


2

Two gears are connected and the larger gear drives the smaller gear. The speed of rotation will __________ and the torque will __________.

61% Answer Correctly

increase, increase

decrease, decrease

increase, decrease

decrease, increase


Solution

Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.


3 What's the mechanical advantage of a wedge that's 5 inches wide and 25 inches long?
83% Answer Correctly
5
8
4.5
1

Solution

The mechanical advantage (MA) of a wedge is its length divided by its thickness:

MA = \( \frac{l}{t} \) = \( \frac{25 in.}{5 in.} \) = 5


4

On Earth, acceleration due to gravity (g) is approximately __________. 

81% Answer Correctly

1 m/s2

1 m/s

9.8 m/s2

6.67 x 10-11 m/s2


Solution

Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects:  \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2


5 If the green box weighs 65 lbs. and 50 lbs. of force is applied 1 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
0.38 ft.
0.77 ft.
0.26 ft.
2.31 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{50 lbs. \times 1 ft.}{65 lbs.} \) = \( \frac{50 ft⋅lb}{65 lbs.} \) = 0.77 ft.