ASVAB Mechanical Comprehension Practice Test 14840 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

opposite

lower than

the same as

higher than


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


2

The mass of an object correlates to the size of the object but ultimately depends on:

66% Answer Correctly

the object's weight

the object's potential energy

the object's density

gravity


Solution

Mass is a measure of the amount of matter in an object.  In general, larger objects have larger mass than smaller objects but mass ultimately depends on how compact (dense) a substance is.


3

What's the last gear in a gear train called?

38% Answer Correctly

driven gear

output gear

idler gear

driver gear


Solution

A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.


4

Friction between two or more solid objects that are not moving relative to each other is called:

73% Answer Correctly

dynamic friction

static friction

gravitational friction

kinetic friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


5 If the green box weighs 55 lbs. and is 9 ft. from the fulcrum, how far from the fulcrum would a 25 lbs. weight need to be placed to balance the lever?
61% Answer Correctly
0 ft.
4.95 ft.
79.2 ft.
19.8 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{55 lbs. \times 9 ft.}{25 lbs.} \) = \( \frac{495 ft⋅lb}{25 lbs.} \) = 19.8 ft.