| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.45 |
| Score | 0% | 69% |
One Horsepower (hp) is equal to how many watts?
1 |
|
9.8 |
|
746 |
|
1492 |
Power is the rate at which work is done, P = w/t, or work per unit time. The watt (W) is the unit for power and is equal to 1 joule (or newton-meter) per second. Horsepower (hp) is another familiar unit of power used primarily for rating internal combustion engines. 1 hp equals 746 watts.
Which of the following is the formula for torque?
τ = r/F |
|
τ = rF |
|
τ = F/r2 |
|
τ = F/r |
Torque measures force applied during rotation: τ = rF. Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).
Which of the following surfaces would have the highest coefficient of friction?
concrete |
|
marble |
|
steel |
|
ice |
Coefficient of friction (μ) represents how much two materials resist sliding across each other. Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.
Which of these is the formula for kinetic energy?
\(KE = {1 \over 2}mv^2\) |
|
\(KE = mgh\) |
|
\(KE = {m \over v^2 }\) |
|
\(KE = {1 \over 2}mh^2\) |
Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.
| 245 ft. | |
| 0.88 ft. | |
| 1.75 ft. | |
| 3.5 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{35 lbs. \times 7 ft.}{70 lbs.} \) = \( \frac{245 ft⋅lb}{70 lbs.} \) = 3.5 ft.