| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
| 30 lbs. | |
| 90 lbs. | |
| 270 lbs. | |
| 180 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{60 lbs. \times 9 ft.}{6 ft.} \) = \( \frac{540 ft⋅lb}{6 ft.} \) = 90 lbs.
On Earth, acceleration due to gravity (g) is approximately __________.
1 m/s |
|
1 m/s2 |
|
9.8 m/s2 |
|
6.67 x 10-11 m/s2 |
Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects: \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2.
For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.
lower than |
|
opposite |
|
higher than |
|
equal to |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
Which of the following is the formula for gravitational potential energy?
\(PE = mg^2h\) |
|
\(PE = { 1 \over 2} mv^2\) |
|
\(PE = mgh\) |
|
\(PE = { 1 \over 2} mg^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
Assuming force applied remains constant, which of the following will result in more work being done?
increasing the coefficient of friction |
|
moving the object with more acceleration |
|
moving the object with more speed |
|
moving the object farther |
Work is accomplished when force is applied to an object: W = Fd where F is force in newtons (N) and d is distance in meters (m). Thus, the more force that must be applied to move an object, the more work is done and the farther an object is moved by exerting force, the more work is done.