| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
The force exerted on an object due to gravity is called:
potential energy |
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mass |
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density |
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weight |
Mass is an intrinsic property of matter and does not vary. Weight is the force exerted on the mass of an object due to gravity and a specific case of Newton's Second Law of Motion. Replace force with weight and acceleration with acceleration due to gravity on Earth (g) and the result is the formula for weight: W = mg or, substituting for g, weight equals mass multiplied by 9.8 m/s2.
A wedge converts force applied to its blunt end into force __________ its inclined surface.
opposite to |
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parallel to |
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perpendicular to |
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along |
The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.
| 8.5 | |
| 21 | |
| 7 | |
| 9 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{210 lbs.}{30 lbs.} \) = 7
The mechanical advantage of a wheel and axle is equal to the:
length of the axle |
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difference in the diameters of the wheels |
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ratio of the diameters of the wheels |
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difference in the lengths of the axles |
A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.
| 75 lbs. | |
| 37.5 lbs. | |
| 18.75 lbs. | |
| 112.5 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{60 lbs. \times 5 ft.}{8 ft.} \) = \( \frac{300 ft⋅lb}{8 ft.} \) = 37.5 lbs.