| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
| 0 ft. | |
| 0.78 ft. | |
| 9.33 ft. | |
| 2.33 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{70 lbs. \times 1 ft.}{30 lbs.} \) = \( \frac{70 ft⋅lb}{30 lbs.} \) = 2.33 ft.
When it comes to force, mass and acceleration have what kind of relationship?
exponential |
|
inverse |
|
logarithmic |
|
linear |
Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.
| 0.89 ft. | |
| 2.67 ft. | |
| 0.67 ft. | |
| 8 ft. |
fAdA = fBdB
For this problem, the equation becomes:
40 lbs. x 4 ft. = 60 lbs. x dB
dB = \( \frac{40 \times 4 ft⋅lb}{60 lbs.} \) = \( \frac{160 ft⋅lb}{60 lbs.} \) = 2.67 ft.
Which of the following surfaces would have the highest coefficient of friction?
marble |
|
steel |
|
concrete |
|
ice |
Coefficient of friction (μ) represents how much two materials resist sliding across each other. Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.
Two gears are connected and the smaller gear drives the larger gear. The speed of rotation will __________ and the torque will __________.
decrease, decrease |
|
increase, increase |
|
increase, decrease |
|
decrease, increase |
Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.