| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
A truck is using a rope to pull a car. Tension in the rope is greatest in which of the following places?
in the middle |
|
tension is equal in all parts of the rope |
|
near the truck |
|
near the car |
Tension is a force that stretches or elongates something. When a cable or rope is used to pull an object, for example, it stretches internally as it accepts the weight that it's moving. Although tension is often treated as applying equally to all parts of a material, it's greater at the places where the material is under the most stress.
A a seesaw / teeter-totter is an example of which of the following?
inclined plane |
|
second-class lever |
|
first-class lever |
|
third-class lever |
A first-class lever is used to increase force or distance while changing the direction of the force. The lever pivots on a fulcrum and, when a force is applied to the lever at one side of the fulcrum, the other end moves in the opposite direction. The position of the fulcrum also defines the mechanical advantage of the lever. If the fulcrum is closer to the force being applied, the load can be moved a greater distance at the expense of requiring a greater input force. If the fulcrum is closer to the load, less force is required but the force must be applied over a longer distance. An example of a first-class lever is a seesaw / teeter-totter.
| 0% | |
| 70% | |
| 35% | |
| 140% |
The mechanical advantage of connected gears is proportional to which characteristic of the gears?
number of teeth |
|
diameter |
|
speed |
|
circumference |
The mechanical advantage (amount of change in speed or torque) of connected gears is proportional to the number of teeth each gear has. Called gear ratio, it's the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear. For example, a gear with 12 teeth connected to a gear with 9 teeth would have a gear ratio of 4:3.
| 11.67 ft. | |
| 2.92 ft. | |
| 75 ft. | |
| 3.89 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{35 lbs. \times 5 ft.}{15 lbs.} \) = \( \frac{175 ft⋅lb}{15 lbs.} \) = 11.67 ft.