ASVAB Mechanical Comprehension Practice Test 232550 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

Collinear forces:

72% Answer Correctly

act in a common plane

are unrelated to each other

act along the same line of action

pass through a common point


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


2

Which of the following statements about this pulley configuration is false?

48% Answer Correctly

Changes the direction of and multiplies the effort force

Only multiplies the effort force

Mechanical advantage is the number of ropes that support the resistance

This is a block and tackle pulley configuration


Solution

A block and tackle is a combination of one or more fixed pulleys and one or more movable pulleys where the fixed pulleys change the direction of the effort force and the movable pulleys multiply it. The mechanical advantage is equal to the number of times the effort force changes direction and can be increased by adding more pulley wheels to the system. An easy way to find the mechanical advantage of a block and tackle pulley system is to count the number of ropes that support the resistance.


3

Friction between two or more solid objects that are not moving relative to each other is called:

73% Answer Correctly

dynamic friction

gravitational friction

kinetic friction

static friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


4

Which of the following is not a type of structural load?

50% Answer Correctly

dead load

occupancy load

wind load

live load


Solution

Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.


5 What is the power output of a 6 hp engine that's 25% efficient?
40% Answer Correctly
275 \( \frac{ft⋅lb}{s} \)
4 \( \frac{ft⋅lb}{s} \)
825 \( \frac{ft⋅lb}{s} \)
3300 \( \frac{ft⋅lb}{s} \)

Solution
\( Efficiency = \frac{Power_{out}}{Power_{in}} \times 100 \)
Solving for power out: \( P_{o} = \frac{E \times P_{i}}{100} \)
Knowing that 1 hp = 550 \( \frac{ft⋅lb}{s} \), Pi becomes 6 hp x 550 \( \frac{ft⋅lb}{s} \) = 3300 \( \frac{ft⋅lb}{s} \)
\( P_{o} = \frac{E \times P_{i}}{100} = \frac{25 \times 3300 \frac{ft⋅lb}{s}}{100} \) \( = \frac{82500 \frac{ft⋅lb}{s}}{100} \) = 825 \( \frac{ft⋅lb}{s} \)