ASVAB Mechanical Comprehension Practice Test 239773 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1 What's the mechanical advantage of a wedge that's 4 inches wide and 36 inches long?
83% Answer Correctly
9
4
18
12

Solution

The mechanical advantage (MA) of a wedge is its length divided by its thickness:

MA = \( \frac{l}{t} \) = \( \frac{36 in.}{4 in.} \) = 9


2

Which of the following statements about this pulley configuration is false?

48% Answer Correctly

This is a block and tackle pulley configuration

Changes the direction of and multiplies the effort force

Mechanical advantage is the number of ropes that support the resistance

Only multiplies the effort force


Solution

A block and tackle is a combination of one or more fixed pulleys and one or more movable pulleys where the fixed pulleys change the direction of the effort force and the movable pulleys multiply it. The mechanical advantage is equal to the number of times the effort force changes direction and can be increased by adding more pulley wheels to the system. An easy way to find the mechanical advantage of a block and tackle pulley system is to count the number of ropes that support the resistance.


3 If the green box weighs 15 lbs. and 65 lbs. of force is applied 5 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
21.67 ft.
0 ft.
7.22 ft.
43.33 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{65 lbs. \times 5 ft.}{15 lbs.} \) = \( \frac{325 ft⋅lb}{15 lbs.} \) = 21.67 ft.


4 If the green box weighs 5 lbs. and is 7 ft. from the fulcrum, how much weight would need to be placed at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 8 ft.?
63% Answer Correctly
40 lbs.
1.09 lbs.
13.13 lbs.
4.38 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{5 lbs. \times 7 ft.}{8 ft.} \) = \( \frac{35 ft⋅lb}{8 ft.} \) = 4.38 lbs.


5

A screw is most like which of the following other simple machines?

50% Answer Correctly

wheel and axle

block and tackle

inclined plane

first-class lever


Solution

A screw is an inclined plane wrapped in ridges (threads) around a cylinder. The distance between these ridges defines the pitch of the screw and this distance is how far the screw advances when it is turned once. The mechanical advantage of a screw is its circumference divided by the pitch.