ASVAB Mechanical Comprehension Practice Test 272797 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

What type of load doesn't create specific stress points or vary with time?

60% Answer Correctly

impact load

static uniformly distributed load

concentrated load

non-uniformly distributed load


Solution

A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.


2 If you lift a 29 lbs. rock 50 ft. from the ground, how much work have you done?
71% Answer Correctly
0 ft⋅lb
700 ft⋅lb
1450 ft⋅lb
2900 ft⋅lb

Solution
Work is force times distance. In this case, the force is the weight of the rock so:
\( W = F \times d \)
\( W = 29 \times 50 \)
\( W = 1450 \)

3

When all forces acting on a system cancel each other out, this is called:

80% Answer Correctly

rest

stasis

potential energy

equilibrium


Solution

When a system is stable or balanced (equilibrium) all forces acting on the system cancel each other out. In the case of torque, equilibrium means that the sum of the anticlockwise moments about a center of rotation equal the sum of the clockwise moments.


4 If 40 lbs. of force is applied 7 ft. from the fulcrum at the blue arrow and the green box is 3 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
0 lbs.
186.67 lbs.
93.33 lbs.
280 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{40 lbs. \times 7 ft.}{3 ft.} \) = \( \frac{280 ft⋅lb}{3 ft.} \) = 93.33 lbs.


5

Boyle's law defines the relationship between pressure and volume as:

57% Answer Correctly

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)

\({P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = {V_1}{V_2}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)