ASVAB Mechanical Comprehension Practice Test 274223 Results

Your Results Global Average
Questions 5 5
Correct 0 2.69
Score 0% 54%

Review

1

Force of friction due to kinetic friction is __________ the force of friction due to static friction.

40% Answer Correctly

lower than

higher than

opposite

the same as


Solution

The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.


2

A a seesaw / teeter-totter is an example of which of the following?

69% Answer Correctly

first-class lever

inclined plane

third-class lever

second-class lever


Solution

A first-class lever is used to increase force or distance while changing the direction of the force. The lever pivots on a fulcrum and, when a force is applied to the lever at one side of the fulcrum, the other end moves in the opposite direction. The position of the fulcrum also defines the mechanical advantage of the lever. If the fulcrum is closer to the force being applied, the load can be moved a greater distance at the expense of requiring a greater input force. If the fulcrum is closer to the load, less force is required but the force must be applied over a longer distance. An example of a first-class lever is a seesaw / teeter-totter.


3 If the radius of the axle is 7 and the radius of the wheel is 8, what is the mechanical advantage of this wheel and axle configuration?
52% Answer Correctly
8
1
0.88
1.14

Solution

The mechanical advantage of a wheel and axle is the input radius divided by the output radius:

MA = \( \frac{r_i}{r_o} \)

In this case, the input radius (where the effort force is being applied) is 8 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{8}{7} \) = 1.14


4 If the green box weighs 35 lbs. and is 7 ft. from the fulcrum, how far from the fulcrum would a 40 lbs. force need to be applied to balance the lever?
58% Answer Correctly
245 ft.
18.38 ft.
6.13 ft.
5 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{35 lbs. \times 7 ft.}{40 lbs.} \) = \( \frac{245 ft⋅lb}{40 lbs.} \) = 6.13 ft.


5 How much work can a 3 hp engine do in 6 seconds?
52% Answer Correctly
0 ft⋅lb
9900 ft⋅lb
12 ft⋅lb
1 ft⋅lb

Solution
Horsepower (hp) is a common measure of power output for complex machines. By definition, a 1 hp machine does 550 ft⋅lb of work in 1 second: 1 hp = 550 ft⋅lb/s. Substituting the variables for this problem gives us:
\( W = 3 hp \times 550 \frac{ft⋅lb}{s} \times 6s = 9900 ft⋅lb \)