| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
Which of the following is the formula for gravitational potential energy?
\(PE = { 1 \over 2} mv^2\) |
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\(PE = { 1 \over 2} mg^2\) |
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\(PE = mgh\) |
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\(PE = mg^2h\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
| 0.55 ft. | |
| 175 ft. | |
| 2.19 ft. | |
| 7 ft. |
fAdA = fBdB
For this problem, the equation becomes:
35 lbs. x 5 ft. = 80 lbs. x dB
dB = \( \frac{35 \times 5 ft⋅lb}{80 lbs.} \) = \( \frac{175 ft⋅lb}{80 lbs.} \) = 2.19 ft.
| 2 | |
| 5 | |
| -5 | |
| 1 |
The mechanical advantage of a wheel and axle lies in the difference in radius between the inner (axle) wheel and the outer wheel. But, this mechanical advantage is only realized when the input effort and load are applied to different wheels. Applying both input effort and load to the same wheel results in a mechanical advantage of 1.
On Earth, acceleration due to gravity (g) is approximately __________.
1 m/s2 |
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6.67 x 10-11 m/s2 |
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9.8 m/s2 |
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1 m/s |
Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects: \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2.
| 7 | |
| 1 | |
| 1.14 | |
| 0.88 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 8 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{8}{7} \) = 1.14