ASVAB Mechanical Comprehension Practice Test 290298 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

Which of the following is not a type of bridge?

74% Answer Correctly

arch

cable

block

truss


Solution

The six basic bridge forms are beam, truss, arch, cantilever, cable, and suspension.


2 If you lift a 27 lbs. rock 30 ft. from the ground, how much work have you done?
70% Answer Correctly
1 ft⋅lb
810 ft⋅lb
1620 ft⋅lb
-3 ft⋅lb

Solution
Work is force times distance. In this case, the force is the weight of the rock so:
\( W = F \times d \)
\( W = 27 \times 30 \)
\( W = 810 \)

3

Which of these is the formula for kinetic energy?

67% Answer Correctly

\(KE = {m \over v^2 }\)

\(KE = {1 \over 2}mh^2\)

\(KE = mgh\)

\(KE = {1 \over 2}mv^2\)


Solution

Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.


4

Which of these will have the most impact on the kinetic energy of an object?

54% Answer Correctly

its weight

its direction

its mass

its speed


Solution

Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.


5 If the handles of a wheelbarrow are 2.5 ft. from the wheel axle and the load is concentrated at a point 0.5 ft. from the axle, how many pounds of load will a 130 lbs. force lift?
47% Answer Correctly
650
26
104
88

Solution
This problem describes a second-class lever and, for a second class lever, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance: Fede = Frdr. In this problem we're looking for resistance force:
\( F_r = \frac{F_e d_e}{d_r} \)
\( F_r = \frac{130 \times 2.5}{0.5} \)
\( F_r = \frac{325.0}{0.5} \)
\( F_r = 650 \)