| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
Which of the following is the formula for gravitational potential energy?
\(PE = mg^2h\) |
|
\(PE = mgh\) |
|
\(PE = { 1 \over 2} mv^2\) |
|
\(PE = { 1 \over 2} mg^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
Friction resists movement in a direction __________ to the movement.
parallel |
|
perpendicular |
|
opposite |
|
normal |
Friction resists movement. Kinetic (also called sliding or dynamic) friction resists movement in a direction opposite to the movement. Because it opposes movement, kinetic friction will eventually bring an object to a stop. An example is a rock that's sliding across ice.
| 10 ft. | |
| 5 ft. | |
| 20 ft. | |
| 80 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{20 lbs. \times 5 ft.}{5 lbs.} \) = \( \frac{100 ft⋅lb}{5 lbs.} \) = 20 ft.
Which of these will have the most impact on the kinetic energy of an object?
its direction |
|
its mass |
|
its weight |
|
its speed |
Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.
| 20 lbs. | |
| 6 lbs. | |
| 26.67 lbs. | |
| 80 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{50 lbs. \times 8 ft.}{5 ft.} \) = \( \frac{400 ft⋅lb}{5 ft.} \) = 80 lbs.