ASVAB Mechanical Comprehension Practice Test 294892 Results

Your Results Global Average
Questions 5 5
Correct 0 3.45
Score 0% 69%

Review

1

The mechanical advantage of a block and tackle is equal to which of the following?

69% Answer Correctly

the number of pulleys

the number of loads

the number of connecting ropes

the number of input forces


Solution

Two or more pulleys used together constitute a block and tackle which, unlike a fixed pulley, does impart mechanical advantage as a function of the number of pulleys that make up the arrangement.  So, for example, a block and tackle with three pulleys would have a mechanical advantage of three.


2

Collinear forces:

73% Answer Correctly

act along the same line of action

act in a common plane

pass through a common point

are unrelated to each other


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


3 If the radius of the axle is 3 and the radius of the wheel is 6, what is the mechanical advantage of this wheel and axle configuration?
52% Answer Correctly
3
2.0
-3
0.5

Solution

The mechanical advantage of a wheel and axle is the input radius divided by the output radius:

MA = \( \frac{r_i}{r_o} \)

In this case, the input radius (where the effort force is being applied) is 6 and the output radius (where the resistance is being applied) is 3 for a mechanical advantage of \( \frac{6}{3} \) = 2.0


4

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

the same as

higher than

lower than

opposite


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


5 If A = 3 ft. and the green box weighs 15 lbs. what is the torque acting on the A side of this lever?
74% Answer Correctly
5 ft⋅lb
0 ft⋅lb
45 ft⋅lb
15 ft⋅lb

Solution
For a lever, torque is weight x distance from the fulcrum which, in this case, is: 15 ft. x 3 lbs. = 45 ft⋅lb