Your Results | Global Average | |
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Questions | 5 | 5 |
Correct | 0 | 2.94 |
Score | 0% | 59% |
Boyle's law defines the relationship between pressure and volume as:
\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\) |
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\(\frac{P_1}{P_2} = {V_1}{V_2}\) |
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\({P_1}{P_2} = {V_1}{V_2}\) |
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\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\) |
Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)
Which of the following is the formula for gravitational potential energy?
\(PE = mgh\) |
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\(PE = mg^2h\) |
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\(PE = { 1 \over 2} mg^2\) |
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\(PE = { 1 \over 2} mv^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
90 ft. | |
16.88 ft. | |
67.5 ft. | |
22.5 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{75 lbs. \times 9 ft.}{10 lbs.} \) = \( \frac{675 ft⋅lb}{10 lbs.} \) = 67.5 ft.
Depending on where you apply effort and resistance, the wheel and axle can multiply:
force or speed |
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speed or power |
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force or distance |
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power or distance |
If you apply the resistance to the axle and the effort to the wheel, the wheel and axle will multiply force and if you apply the resistance to the wheel and the effort to the axle, it will multiply speed.
Collinear forces:
act in a common plane |
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are unrelated to each other |
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act along the same line of action |
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pass through a common point |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.