| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
Concurrent forces:
act along the same line of action |
|
act in a common plane |
|
act in a common dimension |
|
pass through a common point |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.
The principle of moments defines equilibrium in terms of:
torque |
|
power |
|
speed |
|
energy |
According to the principle of moments, you can maintain equilibrium if the moments (forces) tending to clockwise rotation are equal to the moments tending to counterclockwise rotation. Another name for these moments of force is torque.
When all forces acting on a system cancel each other out, this is called:
potential energy |
|
rest |
|
stasis |
|
equilibrium |
When a system is stable or balanced (equilibrium) all forces acting on the system cancel each other out. In the case of torque, equilibrium means that the sum of the anticlockwise moments about a center of rotation equal the sum of the clockwise moments.
| 22 ft. | |
| 5.5 ft. | |
| 2.75 ft. | |
| 55 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{55 lbs. \times 1 ft.}{10 lbs.} \) = \( \frac{55 ft⋅lb}{10 lbs.} \) = 5.5 ft.
| 1.6 ft. | |
| 0 ft. | |
| 0.8 ft. | |
| 0.2 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{20 lbs. \times 1 ft.}{25 lbs.} \) = \( \frac{20 ft⋅lb}{25 lbs.} \) = 0.8 ft.