ASVAB Mechanical Comprehension Practice Test 299779 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

higher than

lower than

opposite

the same as


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


2 If a 60 lbs. weight is placed 1 ft. from the fulcrum at the blue arrow and the green box is 8 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
61% Answer Correctly
60 lbs.
2.5 lbs.
7.5 lbs.
15 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{60 lbs. \times 1 ft.}{8 ft.} \) = \( \frac{60 ft⋅lb}{8 ft.} \) = 7.5 lbs.


3 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
56% Answer Correctly
10.4 psi
4.8 psi
14.4 psi
28.8 psi

Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi


4

The advantage of using a third-class lever is that it increases:

37% Answer Correctly

the speed of the load

the distance traveled by the load

the force applied to the load

the mechanical advantage of the lever


Solution

A third-class lever is used to increase distance traveled by an object in the same direction as the force applied. The fulcrum is at one end of the lever, the object at the other, and the force is applied between them. This lever does not impart a mechanical advantage as the effort force must be greater than the load but does impart extra speed to the load. Examples of third-class levers are shovels and tweezers.


5

Drag is a type of:

82% Answer Correctly

potential energy

friction

work

kinetic energy


Solution

Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.