| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
The work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. This defines which of the following?
conservation of mechanical energy |
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mechanical advantage |
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work-energy theorem |
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Pascal's law |
The work-energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. Simply put, work imparts kinetic energy to the matter upon which the work is being done.
Which of the following represents the force a surface exerts when an object presses against it?
mass |
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counter force |
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friction |
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normal force |
Normal force (FN) represents the force a surface exerts when an object presses against it.
Gear ratio indicates which of the following about two connected gears?
efficiency |
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power conversion |
|
work done |
|
mechanical advantage |
The mechanical advantage (amount of change in speed or torque) of connected gears is proportional to the number of teeth each gear has. Called gear ratio, it's the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear. For example, a gear with 12 teeth connected to a gear with 9 teeth would have a gear ratio of 4:3.
| 16500 ft⋅lb | |
| 0 ft⋅lb | |
| 1 ft⋅lb | |
| 2 ft⋅lb |
| 21 ft. | |
| 84 ft. | |
| 10.5 ft. | |
| 0 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{30 lbs. \times 7 ft.}{10 lbs.} \) = \( \frac{210 ft⋅lb}{10 lbs.} \) = 21 ft.