ASVAB Mechanical Comprehension Practice Test 321524 Results

Your Results Global Average
Questions 5 5
Correct 0 2.79
Score 0% 56%

Review

1 If the green box weighs 50 lbs. and is 3 ft. from the fulcrum, how much weight would need to be placed at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 4 ft.?
63% Answer Correctly
9.38 lbs.
75 lbs.
18.75 lbs.
37.5 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{50 lbs. \times 3 ft.}{4 ft.} \) = \( \frac{150 ft⋅lb}{4 ft.} \) = 37.5 lbs.


2

Gear ratio indicates which of the following about two connected gears?

59% Answer Correctly

mechanical advantage

efficiency

power conversion

work done


Solution

The mechanical advantage (amount of change in speed or torque) of connected gears is proportional to the number of teeth each gear has. Called gear ratio, it's the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear.  For example, a gear with 12 teeth connected to a gear with 9 teeth would have a gear ratio of 4:3.


3 If the green box weighs 10 lbs. and is 7 ft. from the fulcrum, how far from the fulcrum would a 35 lbs. weight need to be placed to balance the lever?
61% Answer Correctly
2 ft.
1 ft.
6 ft.
70 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{10 lbs. \times 7 ft.}{35 lbs.} \) = \( \frac{70 ft⋅lb}{35 lbs.} \) = 2 ft.


4

Force of friction due to kinetic friction is __________ the force of friction due to static friction.

40% Answer Correctly

opposite

higher than

lower than

the same as


Solution

The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.


5

Which of the following statements about drag is false?

58% Answer Correctly

the amount of drag depends on the shape of an object

the amount of drag depends on the speed of an object

drag occurs during movement through a fluid

slower objects experience more drag than faster objects


Solution

Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.