| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
| 105 ft⋅lb | |
| 157 ft⋅lb | |
| 315 ft⋅lb | |
| 945 ft⋅lb |
| 0.75 | |
| 1 | |
| 4 | |
| 3 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 3 and the output radius (where the resistance is being applied) is 4 for a mechanical advantage of \( \frac{3}{4} \) = 0.75
The force amplification achieved by using a tool, mechanical device or machine system is called:
efficiency |
|
power |
|
work |
|
mechanical advantage |
Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Such a device utilizes input force and trades off forces against movement to amplify and/or change its direction.
The force exerted on an object due to gravity is called:
mass |
|
weight |
|
potential energy |
|
density |
Mass is an intrinsic property of matter and does not vary. Weight is the force exerted on the mass of an object due to gravity and a specific case of Newton's Second Law of Motion. Replace force with weight and acceleration with acceleration due to gravity on Earth (g) and the result is the formula for weight: W = mg or, substituting for g, weight equals mass multiplied by 9.8 m/s2.
| 15 lbs. | |
| 7.98 lbs. | |
| 9.12 lbs. | |
| 48.25 lbs. |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 8 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{8}{7} \) = 1.14
MA = \( \frac{load}{effort} \) so effort = \( \frac{load}{MA} \) = \( \frac{55 lbs.}{1.14} \) = 48.25 lbs.