| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.55 |
| Score | 0% | 71% |
A ramp is an example of which kind of simple machine?
wedge |
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none of these |
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first-class lever |
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inclined plane |
An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.
An object's resistance to changes in direction is known as:
inertia |
|
weight |
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kinetic energy |
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mass |
The more mass a substance has the more force is required to move it or to change its direction. This resistance to changes in direction is known as inertia.
| 3.6 | |
| -5 | |
| 4 | |
| 1 |
Mechanical advantage (MA) can be calculated knowing only the distance the effort (blue arrow) moves and the distance the resistance (green box) moves. The equation is:
MA = \( \frac{E_d}{R_d} \)
where Ed is the effort distance and Rd is the resistance distance. For this problem, the equation becomes:
MA = \( \frac{6 ft.}{1.5 ft.} \) = 4
You might be wondering how having an effort distance of 4 times the resistance distance is an advantage. Remember the principle of moments. For a lever in equilibrium the effort torque equals the resistance torque. Because torque is force x distance, if the effort distance is 4 times the resistance distance, the effort force must be \( \frac{1}{4} \) the resistance force. You're trading moving 4 times the distance for only having to use \( \frac{1}{4} \) the force.
| 3 ft. | |
| 33 ft. | |
| 50 ft. | |
| 0 ft. |
Win = Wout
Feffort x deffort = Fresistance x dresistance
In this problem, the effort work is 300 ft⋅lb and the resistance force is 100 lbs. and we need to calculate the resistance distance:
Win = Fresistance x dresistance
300 ft⋅lb = 100 lbs. x dresistance
dresistance = \( \frac{300ft⋅lb}{100 lbs.} \) = 3 ft.
| 5.25 ft. | |
| 140 ft. | |
| 15.75 ft. | |
| 2 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{45 lbs. \times 7 ft.}{20 lbs.} \) = \( \frac{315 ft⋅lb}{20 lbs.} \) = 15.75 ft.