ASVAB Mechanical Comprehension Practice Test 340259 Results

Your Results Global Average
Questions 5 5
Correct 0 3.37
Score 0% 67%

Review

1

The force amplification achieved by using a tool, mechanical device or machine system is called:

80% Answer Correctly

work

efficiency

mechanical advantage

power


Solution

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Such a device utilizes input force and trades off forces against movement to amplify and/or change its direction.


2

Which of the following will increase the mechanical advantage of a second-class lever?

55% Answer Correctly

move the fulcrum between the force and the object being lifted

move the object being lifted farther away from the fulcrum

move the object being lifted closer to the fulcrum

decrease the length of the lever


Solution

A second-class lever is used to increase force on an object in the same direction as the force is applied. This lever requires a smaller force to lift a larger load but the force must be applied over a greater distance. The fulcrum is placed at one end of the lever and mechanical advantage increases as the object being lifted is moved closer to the fulcrum or the length of the lever is increased. An example of a second-class lever is a wheelbarrow.


3

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

the same as

higher than

opposite

lower than


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


4

Sam can do 50 ft. lb. of work in 2 minutes and 5 seconds. What would Sam have to do to increase his power output?

63% Answer Correctly

do the work in 3 minutes

do the work in 2 minutes

do 25 ft. lb. of work in 2 minutes 5 seconds

do 100 ft. lb. of work in 4 minutes 12 seconds


Solution

Power is the rate of doing work or \(\frac{W}{t}\). To increase power, increase the work being done in the same amount of time or do the same amount of work in less time.


5 If 40 lbs. of force is applied 5 ft. from the fulcrum at the blue arrow and the green box is 1 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
0 lbs.
800 lbs.
200 lbs.
400 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{40 lbs. \times 5 ft.}{1 ft.} \) = \( \frac{200 ft⋅lb}{1 ft.} \) = 200 lbs.