| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.54 |
| Score | 0% | 71% |
The steering wheel of a car is an example of which type of simple machine?
fixed pulley |
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wheel and axle |
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first-class lever |
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block and tackle |
A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.
Which of the following is the formula for hydraulic pressure?
P = F/A2 |
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P = F/A |
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P = FA |
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P = FA2 |
Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).
The mechanical advantage of a wheel and axle is equal to the:
length of the axle |
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difference in the diameters of the wheels |
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ratio of the diameters of the wheels |
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difference in the lengths of the axles |
A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.
| 9 | |
| 10.5 | |
| 27 | |
| 14 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{450 lbs.}{50 lbs.} \) = 9
| 25 lbs. | |
| 37.5 lbs. | |
| 1 lbs. | |
| 12.5 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{5 lbs. \times 5 ft.}{2 ft.} \) = \( \frac{25 ft⋅lb}{2 ft.} \) = 12.5 lbs.