ASVAB Mechanical Comprehension Practice Test 350714 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Concurrent forces:

55% Answer Correctly

act in a common dimension

act in a common plane

pass through a common point

act along the same line of action


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


2

The mechanical advantage of a block and tackle is equal to which of the following?

69% Answer Correctly

the number of pulleys

the number of connecting ropes

the number of loads

the number of input forces


Solution

Two or more pulleys used together constitute a block and tackle which, unlike a fixed pulley, does impart mechanical advantage as a function of the number of pulleys that make up the arrangement.  So, for example, a block and tackle with three pulleys would have a mechanical advantage of three.


3 If input effort is 800 ft⋅lb, what output effort will be produced by a machine with a mechanical advantage of 9?
79% Answer Correctly
3600ft⋅lb
88ft⋅lb
28800ft⋅lb
7200 ft⋅lb

Solution
Mechanical advantage is the ratio of output force to input force and tells us by how many times a machine multiplies input effort. So, a machine with a mechanical advantage of 9 will multiply an input effort of 800 ft⋅lb by 9 to produce an output effort of 7200 ft⋅lb.

4

According to Boyle's law, for a fixed amount of gas kept at a fixed temperature, which of the following are inversely proportional?

63% Answer Correctly

pressure, volume

pressure, density

volume, mass

density, volume


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional".


5

Force of friction due to kinetic friction is __________ the force of friction due to static friction.

40% Answer Correctly

lower than

opposite

higher than

the same as


Solution

The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.